Distance from Pawtucket to Aleksandrow Lodzki
The shortest distance (air line) between Pawtucket and Aleksandrow Lodzki is 4,057.02 mi (6,529.14 km).
How far is Pawtucket from Aleksandrow Lodzki
Pawtucket is located in Rhode Island, United States within 41° 52' 27.84" N -72° 37' 32.52" W (41.8744, -71.3743) coordinates. The local time in Pawtucket is 13:47 (30.08.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 19:47 (30.08.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,057.02 miles which is equal to 6,529.14 km.
Pawtucket, Rhode Island, United States
Related Distances from Pawtucket
Aleksandrow Lodzki, Łódzki, Poland