Distance from Patchogue to Wallenhorst
The shortest distance (air line) between Patchogue and Wallenhorst is 3,724.85 mi (5,994.56 km).
How far is Patchogue from Wallenhorst
Patchogue is located in New York, United States within 40° 45' 43.56" N -74° 58' 53.4" W (40.7621, -73.0185) coordinates. The local time in Patchogue is 05:30 (20.12.2025)
Wallenhorst is located in Osnabrück; Landkreis, Germany within 52° 21' 0" N 8° 1' 0.12" E (52.3500, 8.0167) coordinates. The local time in Wallenhorst is 11:30 (20.12.2025)
The calculated flying distance from Wallenhorst to Wallenhorst is 3,724.85 miles which is equal to 5,994.56 km.
Patchogue, New York, United States
Related Distances from Patchogue
Wallenhorst, Osnabrück; Landkreis, Germany