Distance from Patchogue to Fontainebleau
The shortest distance (air line) between Patchogue and Fontainebleau is 3,609.53 mi (5,808.98 km).
How far is Patchogue from Fontainebleau
Patchogue is located in New York, United States within 40° 45' 43.56" N -74° 58' 53.4" W (40.7621, -73.0185) coordinates. The local time in Patchogue is 15:00 (10.08.2025)
Fontainebleau is located in Seine-et-Marne, France within 48° 24' 32.04" N 2° 42' 6.12" E (48.4089, 2.7017) coordinates. The local time in Fontainebleau is 21:00 (10.08.2025)
The calculated flying distance from Fontainebleau to Fontainebleau is 3,609.53 miles which is equal to 5,808.98 km.
Patchogue, New York, United States
Related Distances from Patchogue
Fontainebleau, Seine-et-Marne, France