Distance from Parma Heights to Aleksandrow Lodzki
The shortest distance (air line) between Parma Heights and Aleksandrow Lodzki is 4,455.83 mi (7,170.97 km).
How far is Parma Heights from Aleksandrow Lodzki
Parma Heights is located in Ohio, United States within 41° 23' 11.4" N -82° 14' 10.68" W (41.3865, -81.7637) coordinates. The local time in Parma Heights is 05:10 (29.08.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 11:10 (29.08.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,455.83 miles which is equal to 7,170.97 km.
Parma Heights, Ohio, United States
Related Distances from Parma Heights
Aleksandrow Lodzki, Łódzki, Poland