Distance from Palm Harbor to San Gregorio di Catania
The shortest distance (air line) between Palm Harbor and San Gregorio di Catania is 5,456.25 mi (8,780.99 km).
How far is Palm Harbor from San Gregorio di Catania
Palm Harbor is located in Florida, United States within 28° 5' 4.92" N -83° 15' 6.84" W (28.0847, -82.7481) coordinates. The local time in Palm Harbor is 12:40 (01.11.2025)
San Gregorio di Catania is located in Catania, Italy within 37° 34' 0.12" N 15° 7' 0.12" E (37.5667, 15.1167) coordinates. The local time in San Gregorio di Catania is 18:40 (01.11.2025)
The calculated flying distance from San Gregorio di Catania to San Gregorio di Catania is 5,456.25 miles which is equal to 8,780.99 km.
Palm Harbor, Florida, United States
Related Distances from Palm Harbor
San Gregorio di Catania, Catania, Italy