Distance from Palm Harbor to La Puebla de Cazalla
The shortest distance (air line) between Palm Harbor and La Puebla de Cazalla is 4,425.35 mi (7,121.92 km).
How far is Palm Harbor from La Puebla de Cazalla
Palm Harbor is located in Florida, United States within 28° 5' 4.92" N -83° 15' 6.84" W (28.0847, -82.7481) coordinates. The local time in Palm Harbor is 21:30 (17.11.2025)
La Puebla de Cazalla is located in Sevilla, Spain within 37° 13' 19.92" N -6° 41' 15" W (37.2222, -5.3125) coordinates. The local time in La Puebla de Cazalla is 03:30 (18.11.2025)
The calculated flying distance from La Puebla de Cazalla to La Puebla de Cazalla is 4,425.35 miles which is equal to 7,121.92 km.
Palm Harbor, Florida, United States
Related Distances from Palm Harbor
La Puebla de Cazalla, Sevilla, Spain