Distance from Palm Harbor to Aleksandrow Lodzki
The shortest distance (air line) between Palm Harbor and Aleksandrow Lodzki is 5,192.76 mi (8,356.95 km).
How far is Palm Harbor from Aleksandrow Lodzki
Palm Harbor is located in Florida, United States within 28° 5' 4.92" N -83° 15' 6.84" W (28.0847, -82.7481) coordinates. The local time in Palm Harbor is 23:48 (08.11.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 05:48 (09.11.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 5,192.76 miles which is equal to 8,356.95 km.
Palm Harbor, Florida, United States
Related Distances from Palm Harbor
Aleksandrow Lodzki, Łódzki, Poland