Distance from Oxon Hill to Walnut Park
The shortest distance (air line) between Oxon Hill and Walnut Park is 2,299.09 mi (3,700.02 km).
How far is Oxon Hill from Walnut Park
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 20:02 (18.12.2025)
Walnut Park is located in California, United States within 33° 58' 5.52" N -119° 46' 40.8" W (33.9682, -118.2220) coordinates. The local time in Walnut Park is 17:02 (18.12.2025)
The calculated flying distance from Walnut Park to Walnut Park is 2,299.09 miles which is equal to 3,700.02 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Walnut Park, California, United States