Distance from Oxon Hill to Steenokkerzeel
The shortest distance (air line) between Oxon Hill and Steenokkerzeel is 3,869.79 mi (6,227.82 km).
How far is Oxon Hill from Steenokkerzeel
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 02:48 (01.08.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 08:48 (01.08.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,869.79 miles which is equal to 6,227.82 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium