Distance from Oxon Hill to Sapulpa
The shortest distance (air line) between Oxon Hill and Sapulpa is 1,065.26 mi (1,714.38 km).
How far is Oxon Hill from Sapulpa
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 03:38 (18.12.2025)
Sapulpa is located in Oklahoma, United States within 36° 0' 32.76" N -97° 53' 58.92" W (36.0091, -96.1003) coordinates. The local time in Sapulpa is 02:38 (18.12.2025)
The calculated flying distance from Sapulpa to Sapulpa is 1,065.26 miles which is equal to 1,714.38 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Sapulpa, Oklahoma, United States