Distance from Oxon Hill to Sanford
The shortest distance (air line) between Oxon Hill and Sanford is 733.49 mi (1,180.43 km).
How far is Oxon Hill from Sanford
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 09:08 (16.12.2025)
Sanford is located in Florida, United States within 28° 47' 20.76" N -82° 43' 27.48" W (28.7891, -81.2757) coordinates. The local time in Sanford is 09:08 (16.12.2025)
The calculated flying distance from Sanford to Sanford is 733.49 miles which is equal to 1,180.43 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Sanford, Florida, United States