Distance from Oxon Hill to Kampenhout
The shortest distance (air line) between Oxon Hill and Kampenhout is 3,870.89 mi (6,229.60 km).
How far is Oxon Hill from Kampenhout
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 00:20 (01.08.2025)
Kampenhout is located in Arr. Halle-Vilvoorde, Belgium within 50° 56' 28.68" N 4° 32' 58.56" E (50.9413, 4.5496) coordinates. The local time in Kampenhout is 06:20 (01.08.2025)
The calculated flying distance from Kampenhout to Kampenhout is 3,870.89 miles which is equal to 6,229.60 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Kampenhout, Arr. Halle-Vilvoorde, Belgium