Distance from Oxon Hill to Dimitrovgrad
The shortest distance (air line) between Oxon Hill and Dimitrovgrad is 4,883.72 mi (7,859.58 km).
How far is Oxon Hill from Dimitrovgrad
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 04:37 (02.08.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 10:37 (02.08.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 4,883.72 miles which is equal to 7,859.58 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Dimitrovgrad, Pirotska oblast, Serbia