Distance from Oshkosh to Diepenbeek
The shortest distance (air line) between Oshkosh and Diepenbeek is 4,109.41 mi (6,613.45 km).
How far is Oshkosh from Diepenbeek
Oshkosh is located in Wisconsin, United States within 44° 1' 21.72" N -89° 26' 17.16" W (44.0227, -88.5619) coordinates. The local time in Oshkosh is 11:20 (29.07.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 18:20 (29.07.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,109.41 miles which is equal to 6,613.45 km.
Oshkosh, Wisconsin, United States
Related Distances from Oshkosh
Diepenbeek, Arr. Hasselt, Belgium