Distance from Oranienburg to Petersburg
The shortest distance (air line) between Oranienburg and Petersburg is 4,254.22 mi (6,846.50 km).
How far is Oranienburg from Petersburg
Oranienburg is located in Oberhavel, Germany within 52° 45' 15.84" N 13° 14' 12.84" E (52.7544, 13.2369) coordinates. The local time in Oranienburg is 12:31 (16.12.2025)
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 06:31 (16.12.2025)
The calculated flying distance from Petersburg to Petersburg is 4,254.22 miles which is equal to 6,846.50 km.
Oranienburg, Oberhavel, Germany
Related Distances from Oranienburg
Petersburg, Virginia, United States