Distance from Old Jamestown to Aleksandrow Lodzki
The shortest distance (air line) between Old Jamestown and Aleksandrow Lodzki is 4,880.54 mi (7,854.48 km).
How far is Old Jamestown from Aleksandrow Lodzki
Old Jamestown is located in Missouri, United States within 38° 50' 21.84" N -91° 42' 55.08" W (38.8394, -90.2847) coordinates. The local time in Old Jamestown is 15:15 (29.08.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 22:15 (29.08.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,880.54 miles which is equal to 7,854.48 km.
Old Jamestown, Missouri, United States
Related Distances from Old Jamestown
Aleksandrow Lodzki, Łódzki, Poland