Distance from Old Jamestown to Aleksandrovac
The shortest distance (air line) between Old Jamestown and Aleksandrovac is 5,317.47 mi (8,557.64 km).
How far is Old Jamestown from Aleksandrovac
Old Jamestown is located in Missouri, United States within 38° 50' 21.84" N -91° 42' 55.08" W (38.8394, -90.2847) coordinates. The local time in Old Jamestown is 20:52 (04.09.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 03:52 (05.09.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,317.47 miles which is equal to 8,557.64 km.
Old Jamestown, Missouri, United States
Related Distances from Old Jamestown
Aleksandrovac, Rasinska oblast, Serbia