Distance from New Providence to Diepenbeek
The shortest distance (air line) between New Providence and Diepenbeek is 3,717.29 mi (5,982.40 km).
How far is New Providence from Diepenbeek
New Providence is located in New Jersey, United States within 40° 41' 58.56" N -75° 35' 47.4" W (40.6996, -74.4035) coordinates. The local time in New Providence is 21:34 (31.07.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 03:34 (01.08.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,717.29 miles which is equal to 5,982.40 km.
New Providence, New Jersey, United States
Related Distances from New Providence
Diepenbeek, Arr. Hasselt, Belgium