Distance from Montgomery to Sveti Ivan Zelina
The shortest distance (air line) between Montgomery and Sveti Ivan Zelina is 5,187.73 mi (8,348.85 km).
How far is Montgomery from Sveti Ivan Zelina
Montgomery is located in Alabama, United States within 32° 20' 53.52" N -87° 43' 59.52" W (32.3482, -86.2668) coordinates. The local time in Montgomery is 11:44 (30.07.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 18:44 (30.07.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,187.73 miles which is equal to 8,348.85 km.
Montgomery, Alabama, United States
Related Distances from Montgomery
Sveti Ivan Zelina, Zagrebačka županija, Croatia