Distance from Montechiarugolo to Sentrupert
The shortest distance (air line) between Montechiarugolo and Sentrupert is 243.37 mi (391.67 km).
How far is Montechiarugolo from Sentrupert
Montechiarugolo is located in Parma, Italy within 44° 41' 36.24" N 10° 25' 20.64" E (44.6934, 10.4224) coordinates. The local time in Montechiarugolo is 08:38 (30.08.2025)
Sentrupert is located in Jugovzhodna Slovenija, Slovenia within 45° 58' 36.84" N 15° 5' 22.92" E (45.9769, 15.0897) coordinates. The local time in Sentrupert is 08:38 (30.08.2025)
The calculated flying distance from Sentrupert to Sentrupert is 243.37 miles which is equal to 391.67 km.
Related Distances from Montechiarugolo
Sentrupert, Jugovzhodna Slovenija, Slovenia