Distance from Montechiarugolo to Selnica ob Dravi
The shortest distance (air line) between Montechiarugolo and Selnica ob Dravi is 276.62 mi (445.17 km).
How far is Montechiarugolo from Selnica ob Dravi
Montechiarugolo is located in Parma, Italy within 44° 41' 36.24" N 10° 25' 20.64" E (44.6934, 10.4224) coordinates. The local time in Montechiarugolo is 07:22 (30.08.2025)
Selnica ob Dravi is located in Podravska, Slovenia within 46° 33' 5.04" N 15° 29' 40.92" E (46.5514, 15.4947) coordinates. The local time in Selnica ob Dravi is 07:22 (30.08.2025)
The calculated flying distance from Selnica ob Dravi to Selnica ob Dravi is 276.62 miles which is equal to 445.17 km.
Related Distances from Montechiarugolo
Selnica ob Dravi, Podravska, Slovenia