Distance from Montechiarugolo to Alexandria
The shortest distance (air line) between Montechiarugolo and Alexandria is 737.61 mi (1,187.07 km).
How far is Montechiarugolo from Alexandria
Montechiarugolo is located in Parma, Italy within 44° 41' 36.24" N 10° 25' 20.64" E (44.6934, 10.4224) coordinates. The local time in Montechiarugolo is 15:07 (27.08.2025)
Alexandria is located in Teleorman, Romania within 43° 58' 6.96" N 25° 19' 59.88" E (43.9686, 25.3333) coordinates. The local time in Alexandria is 16:07 (27.08.2025)
The calculated flying distance from Alexandria to Alexandria is 737.61 miles which is equal to 1,187.07 km.
Related Distances from Montechiarugolo
Alexandria, Teleorman, Romania