Distance from Montechiarugolo to Aleksandrovac
The shortest distance (air line) between Montechiarugolo and Aleksandrovac is 534.10 mi (859.56 km).
How far is Montechiarugolo from Aleksandrovac
Montechiarugolo is located in Parma, Italy within 44° 41' 36.24" N 10° 25' 20.64" E (44.6934, 10.4224) coordinates. The local time in Montechiarugolo is 13:14 (28.08.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 13:14 (28.08.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 534.10 miles which is equal to 859.56 km.
Related Distances from Montechiarugolo
Aleksandrovac, Rasinska oblast, Serbia