Distance from Monrovia to Cesky Tesin
The shortest distance (air line) between Monrovia and Cesky Tesin is 6,060.00 mi (9,752.62 km).
How far is Monrovia from Cesky Tesin
Monrovia is located in California, United States within 34° 9' 54" N -118° 0' 28.44" W (34.1650, -117.9921) coordinates. The local time in Monrovia is 12:33 (30.07.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 21:33 (30.07.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 6,060.00 miles which is equal to 9,752.62 km.
Monrovia, California, United States
Related Distances from Monrovia
Cesky Tesin, Moravskoslezský kraj, Czechia