Distance from Monrovia to Argenteuil
The shortest distance (air line) between Monrovia and Argenteuil is 5,623.02 mi (9,049.38 km).
How far is Monrovia from Argenteuil
Monrovia is located in California, United States within 34° 9' 54" N -118° 0' 28.44" W (34.1650, -117.9921) coordinates. The local time in Monrovia is 23:55 (03.08.2025)
Argenteuil is located in Val-d’Oise, France within 48° 57' 0" N 2° 15' 0" E (48.9500, 2.2500) coordinates. The local time in Argenteuil is 08:55 (04.08.2025)
The calculated flying distance from Argenteuil to Argenteuil is 5,623.02 miles which is equal to 9,049.38 km.
Monrovia, California, United States
Related Distances from Monrovia
Argenteuil, Val-d’Oise, France