Distance from Moerdijk to Sioux Falls
The shortest distance (air line) between Moerdijk and Sioux Falls is 4,362.36 mi (7,020.55 km).
How far is Moerdijk from Sioux Falls
Moerdijk is located in West-Noord-Brabant, Netherlands within 51° 38' 60" N 4° 35' 60" E (51.6500, 4.6000) coordinates. The local time in Moerdijk is 14:12 (26.08.2025)
Sioux Falls is located in South Dakota, United States within 43° 32' 22.56" N -97° 16' 8.04" W (43.5396, -96.7311) coordinates. The local time in Sioux Falls is 07:12 (26.08.2025)
The calculated flying distance from Sioux Falls to Sioux Falls is 4,362.36 miles which is equal to 7,020.55 km.
Moerdijk, West-Noord-Brabant, Netherlands
Related Distances from Moerdijk
Sioux Falls, South Dakota, United States