Distance from Moerdijk to Oxon Hill
The shortest distance (air line) between Moerdijk and Oxon Hill is 3,855.04 mi (6,204.09 km).
How far is Moerdijk from Oxon Hill
Moerdijk is located in West-Noord-Brabant, Netherlands within 51° 38' 60" N 4° 35' 60" E (51.6500, 4.6000) coordinates. The local time in Moerdijk is 18:08 (24.08.2025)
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 12:08 (24.08.2025)
The calculated flying distance from Oxon Hill to Oxon Hill is 3,855.04 miles which is equal to 6,204.09 km.
Moerdijk, West-Noord-Brabant, Netherlands
Related Distances from Moerdijk
Oxon Hill, Maryland, United States