Distance from Mint Hill to Dimitrovgrad
The shortest distance (air line) between Mint Hill and Dimitrovgrad is 5,201.02 mi (8,370.24 km).
How far is Mint Hill from Dimitrovgrad
Mint Hill is located in North Carolina, United States within 35° 10' 41.88" N -81° 20' 49.92" W (35.1783, -80.6528) coordinates. The local time in Mint Hill is 23:29 (29.07.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 05:29 (30.07.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,201.02 miles which is equal to 8,370.24 km.
Mint Hill, North Carolina, United States
Related Distances from Mint Hill
Dimitrovgrad, Pirotska oblast, Serbia