Distance from Mesquite to Aleksandrow Lodzki
The shortest distance (air line) between Mesquite and Aleksandrow Lodzki is 5,427.82 mi (8,735.23 km).
How far is Mesquite from Aleksandrow Lodzki
Mesquite is located in Texas, United States within 32° 45' 36.72" N -97° 24' 48.6" W (32.7602, -96.5865) coordinates. The local time in Mesquite is 23:07 (31.08.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 06:07 (01.09.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 5,427.82 miles which is equal to 8,735.23 km.
Mesquite, Texas, United States
Related Distances from Mesquite
Aleksandrow Lodzki, Łódzki, Poland