Distance from Manhattan Beach to Savigny-le-Temple
The shortest distance (air line) between Manhattan Beach and Savigny-le-Temple is 5,680.37 mi (9,141.66 km).
How far is Manhattan Beach from Savigny-le-Temple
Manhattan Beach is located in California, United States within 33° 53' 21.84" N -119° 36' 11.88" W (33.8894, -118.3967) coordinates. The local time in Manhattan Beach is 19:45 (13.08.2025)
Savigny-le-Temple is located in Seine-et-Marne, France within 48° 35' 2.76" N 2° 34' 59.52" E (48.5841, 2.5832) coordinates. The local time in Savigny-le-Temple is 04:45 (14.08.2025)
The calculated flying distance from Savigny-le-Temple to Savigny-le-Temple is 5,680.37 miles which is equal to 9,141.66 km.
Manhattan Beach, California, United States
Related Distances from Manhattan Beach
Savigny-le-Temple, Seine-et-Marne, France