Distance from Manhattan Beach to Bad Liebenwerda
The shortest distance (air line) between Manhattan Beach and Bad Liebenwerda is 5,852.93 mi (9,419.37 km).
How far is Manhattan Beach from Bad Liebenwerda
Manhattan Beach is located in California, United States within 33° 53' 21.84" N -119° 36' 11.88" W (33.8894, -118.3967) coordinates. The local time in Manhattan Beach is 11:03 (11.08.2025)
Bad Liebenwerda is located in Elbe-Elster, Germany within 51° 31' 0.12" N 13° 24' 0" E (51.5167, 13.4000) coordinates. The local time in Bad Liebenwerda is 20:03 (11.08.2025)
The calculated flying distance from Bad Liebenwerda to Bad Liebenwerda is 5,852.93 miles which is equal to 9,419.37 km.
Manhattan Beach, California, United States
Related Distances from Manhattan Beach
Bad Liebenwerda, Elbe-Elster, Germany