Distance from Lwowek Slaski to Oxon Hill
The shortest distance (air line) between Lwowek Slaski and Oxon Hill is 4,300.13 mi (6,920.40 km).
How far is Lwowek Slaski from Oxon Hill
Lwowek Slaski is located in Jeleniogórski, Poland within 51° 7' 0.12" N 15° 34' 59.88" E (51.1167, 15.5833) coordinates. The local time in Lwowek Slaski is 22:26 (16.08.2025)
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 16:26 (16.08.2025)
The calculated flying distance from Oxon Hill to Oxon Hill is 4,300.13 miles which is equal to 6,920.40 km.
Lwowek Slaski, Jeleniogórski, Poland
Related Distances from Lwowek Slaski
Oxon Hill, Maryland, United States