Distance from Lwowek Slaski to Dix Hills
The shortest distance (air line) between Lwowek Slaski and Dix Hills is 4,064.55 mi (6,541.27 km).
How far is Lwowek Slaski from Dix Hills
Lwowek Slaski is located in Jeleniogórski, Poland within 51° 7' 0.12" N 15° 34' 59.88" E (51.1167, 15.5833) coordinates. The local time in Lwowek Slaski is 13:44 (02.08.2025)
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 07:44 (02.08.2025)
The calculated flying distance from Dix Hills to Dix Hills is 4,064.55 miles which is equal to 6,541.27 km.
Lwowek Slaski, Jeleniogórski, Poland
Related Distances from Lwowek Slaski
Dix Hills, New York, United States