Distance from Lwowek Slaski to Austintown
The shortest distance (air line) between Lwowek Slaski and Austintown is 4,328.19 mi (6,965.54 km).
How far is Lwowek Slaski from Austintown
Lwowek Slaski is located in Jeleniogórski, Poland within 51° 7' 0.12" N 15° 34' 59.88" E (51.1167, 15.5833) coordinates. The local time in Lwowek Slaski is 17:08 (27.07.2025)
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 11:08 (27.07.2025)
The calculated flying distance from Austintown to Austintown is 4,328.19 miles which is equal to 6,965.54 km.
Lwowek Slaski, Jeleniogórski, Poland
Related Distances from Lwowek Slaski
Austintown, Ohio, United States