Distance from Lukovica to Dix Hills
The shortest distance (air line) between Lukovica and Dix Hills is 4,193.67 mi (6,749.06 km).
How far is Lukovica from Dix Hills
Lukovica is located in Osrednjeslovenska, Slovenia within 46° 10' 6.96" N 14° 41' 21.12" E (46.1686, 14.6892) coordinates. The local time in Lukovica is 04:09 (22.12.2025)
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 22:09 (21.12.2025)
The calculated flying distance from Dix Hills to Dix Hills is 4,193.67 miles which is equal to 6,749.06 km.
Lukovica, Osrednjeslovenska, Slovenia
Related Distances from Lukovica
Dix Hills, New York, United States