Distance from Lukovica to Christiansburg
The shortest distance (air line) between Lukovica and Christiansburg is 4,647.24 mi (7,479.01 km).
How far is Lukovica from Christiansburg
Lukovica is located in Osrednjeslovenska, Slovenia within 46° 10' 6.96" N 14° 41' 21.12" E (46.1686, 14.6892) coordinates. The local time in Lukovica is 20:12 (25.12.2025)
Christiansburg is located in Virginia, United States within 37° 8' 26.16" N -81° 35' 47.04" W (37.1406, -80.4036) coordinates. The local time in Christiansburg is 14:12 (25.12.2025)
The calculated flying distance from Christiansburg to Christiansburg is 4,647.24 miles which is equal to 7,479.01 km.
Lukovica, Osrednjeslovenska, Slovenia
Related Distances from Lukovica
Christiansburg, Virginia, United States