Distance from Lovejoy to Sint-Andries
The shortest distance (air line) between Lovejoy and Sint-Andries is 4,360.42 mi (7,017.42 km).
How far is Lovejoy from Sint-Andries
Lovejoy is located in Georgia, United States within 33° 26' 33.36" N -85° 40' 56.28" W (33.4426, -84.3177) coordinates. The local time in Lovejoy is 00:05 (30.07.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 06:05 (30.07.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,360.42 miles which is equal to 7,017.42 km.
Lovejoy, Georgia, United States
Related Distances from Lovejoy
Sint-Andries, Arr. Brugge, Belgium