Distance from Lompoc to Siemianowice Slaskie
The shortest distance (air line) between Lompoc and Siemianowice Slaskie is 6,068.08 mi (9,765.63 km).
How far is Lompoc from Siemianowice Slaskie
Lompoc is located in California, United States within 34° 39' 42.48" N -121° 31' 42.96" W (34.6618, -120.4714) coordinates. The local time in Lompoc is 05:52 (27.08.2025)
Siemianowice Slaskie is located in Katowicki, Poland within 50° 16' 32.88" N 18° 59' 8.88" E (50.2758, 18.9858) coordinates. The local time in Siemianowice Slaskie is 14:52 (27.08.2025)
The calculated flying distance from Siemianowice Slaskie to Siemianowice Slaskie is 6,068.08 miles which is equal to 9,765.63 km.
Lompoc, California, United States
Related Distances from Lompoc
Siemianowice Slaskie, Katowicki, Poland