Distance from Lompoc to Ozarow Mazowiecki
The shortest distance (air line) between Lompoc and Ozarow Mazowiecki is 5,995.19 mi (9,648.32 km).
How far is Lompoc from Ozarow Mazowiecki
Lompoc is located in California, United States within 34° 39' 42.48" N -121° 31' 42.96" W (34.6618, -120.4714) coordinates. The local time in Lompoc is 04:45 (27.08.2025)
Ozarow Mazowiecki is located in Warszawski zachodni, Poland within 52° 13' 0.12" N 20° 48' 0" E (52.2167, 20.8000) coordinates. The local time in Ozarow Mazowiecki is 13:45 (27.08.2025)
The calculated flying distance from Ozarow Mazowiecki to Ozarow Mazowiecki is 5,995.19 miles which is equal to 9,648.32 km.
Lompoc, California, United States
Related Distances from Lompoc
Ozarow Mazowiecki, Warszawski zachodni, Poland