Distance from Lindenwold to San Severino Marche
The shortest distance (air line) between Lindenwold and San Severino Marche is 4,341.80 mi (6,987.46 km).
How far is Lindenwold from San Severino Marche
Lindenwold is located in New Jersey, United States within 39° 49' 2.28" N -75° 0' 36.72" W (39.8173, -74.9898) coordinates. The local time in Lindenwold is 20:29 (30.08.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 02:29 (31.08.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 4,341.80 miles which is equal to 6,987.46 km.
Lindenwold, New Jersey, United States
Related Distances from Lindenwold
San Severino Marche, Macerata, Italy