Distance from Lindenhurst to Sajoszentpeter
The shortest distance (air line) between Lindenhurst and Sajoszentpeter is 4,370.23 mi (7,033.20 km).
How far is Lindenhurst from Sajoszentpeter
Lindenhurst is located in New York, United States within 40° 41' 8.88" N -74° 37' 44.4" W (40.6858, -73.3710) coordinates. The local time in Lindenhurst is 07:05 (23.08.2025)
Sajoszentpeter is located in Borsod-Abaúj-Zemplén, Hungary within 48° 13' 0.84" N 20° 43' 5.88" E (48.2169, 20.7183) coordinates. The local time in Sajoszentpeter is 13:05 (23.08.2025)
The calculated flying distance from Sajoszentpeter to Sajoszentpeter is 4,370.23 miles which is equal to 7,033.20 km.
Lindenhurst, New York, United States
Related Distances from Lindenhurst
Sajoszentpeter, Borsod-Abaúj-Zemplén, Hungary