Distance from Lexington Park to Asenovgrad
The shortest distance (air line) between Lexington Park and Asenovgrad is 5,012.18 mi (8,066.33 km).
How far is Lexington Park from Asenovgrad
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 12:46 (30.07.2025)
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 19:46 (30.07.2025)
The calculated flying distance from Asenovgrad to Asenovgrad is 5,012.18 miles which is equal to 8,066.33 km.
Lexington Park, Maryland, United States