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      Distance from Lexington to Villeneuve-Saint-Georges

      The shortest distance (air line) between Lexington and Villeneuve-Saint-Georges is 4,185.67 mi (6,736.19 km).

      How far is Lexington from Villeneuve-Saint-Georges

      Lexington is located in Kentucky, United States within 38° 2' 32.28" N -85° 32' 28.68" W (38.0423, -84.4587) coordinates. The local time in Lexington is 05:44 (10.08.2025)

      Villeneuve-Saint-Georges is located in Val-de-Marne, France within 48° 43' 57" N 2° 26' 58.92" E (48.7325, 2.4497) coordinates. The local time in Villeneuve-Saint-Georges is 11:44 (10.08.2025)

      The calculated flying distance from Villeneuve-Saint-Georges to Villeneuve-Saint-Georges is 4,185.67 miles which is equal to 6,736.19 km.

      Lexington, Kentucky, United States

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      Villeneuve-Saint-Georges, Val-de-Marne, France

      Related Distances to Villeneuve-Saint-Georges