Distance from Lexington to Montceau-les-Mines
The shortest distance (air line) between Lexington and Montceau-les-Mines is 4,329.26 mi (6,967.27 km).
How far is Lexington from Montceau-les-Mines
Lexington is located in Kentucky, United States within 38° 2' 32.28" N -85° 32' 28.68" W (38.0423, -84.4587) coordinates. The local time in Lexington is 22:11 (06.08.2025)
Montceau-les-Mines is located in Saône-et-Loire, France within 46° 40' 0.84" N 4° 22' 8.04" E (46.6669, 4.3689) coordinates. The local time in Montceau-les-Mines is 04:11 (07.08.2025)
The calculated flying distance from Montceau-les-Mines to Montceau-les-Mines is 4,329.26 miles which is equal to 6,967.27 km.
Lexington, Kentucky, United States
Related Distances from Lexington
Montceau-les-Mines, Saône-et-Loire, France