Distance from Lexington to Fontainebleau
The shortest distance (air line) between Lexington and Fontainebleau is 4,205.73 mi (6,768.47 km).
How far is Lexington from Fontainebleau
Lexington is located in Kentucky, United States within 38° 2' 32.28" N -85° 32' 28.68" W (38.0423, -84.4587) coordinates. The local time in Lexington is 02:48 (04.08.2025)
Fontainebleau is located in Seine-et-Marne, France within 48° 24' 32.04" N 2° 42' 6.12" E (48.4089, 2.7017) coordinates. The local time in Fontainebleau is 08:48 (04.08.2025)
The calculated flying distance from Fontainebleau to Fontainebleau is 4,205.73 miles which is equal to 6,768.47 km.
Lexington, Kentucky, United States
Related Distances from Lexington
Fontainebleau, Seine-et-Marne, France