Distance from Lexington to Bad Sassendorf
The shortest distance (air line) between Lexington and Bad Sassendorf is 4,324.27 mi (6,959.25 km).
How far is Lexington from Bad Sassendorf
Lexington is located in Kentucky, United States within 38° 2' 32.28" N -85° 32' 28.68" W (38.0423, -84.4587) coordinates. The local time in Lexington is 23:11 (09.08.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 05:11 (10.08.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,324.27 miles which is equal to 6,959.25 km.
Lexington, Kentucky, United States
Related Distances from Lexington
Bad Sassendorf, Soest, Germany