Distance from Lawrence to Warrensville Heights
The shortest distance (air line) between Lawrence and Warrensville Heights is 744.26 mi (1,197.78 km).
How far is Lawrence from Warrensville Heights
Lawrence is located in Kansas, United States within 38° 57' 34.92" N -96° 44' 8.88" W (38.9597, -95.2642) coordinates. The local time in Lawrence is 17:56 (18.12.2025)
Warrensville Heights is located in Ohio, United States within 41° 26' 10.68" N -82° 28' 40.08" W (41.4363, -81.5222) coordinates. The local time in Warrensville Heights is 18:56 (18.12.2025)
The calculated flying distance from Warrensville Heights to Warrensville Heights is 744.26 miles which is equal to 1,197.78 km.
Lawrence, Kansas, United States
Related Distances from Lawrence
Warrensville Heights, Ohio, United States