Distance from Lawrence to Sveti Ivan Zelina
The shortest distance (air line) between Lawrence and Sveti Ivan Zelina is 5,202.49 mi (8,372.59 km).
How far is Lawrence from Sveti Ivan Zelina
Lawrence is located in Kansas, United States within 38° 57' 34.92" N -96° 44' 8.88" W (38.9597, -95.2642) coordinates. The local time in Lawrence is 08:00 (29.07.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 15:00 (29.07.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,202.49 miles which is equal to 8,372.59 km.
Lawrence, Kansas, United States
Related Distances from Lawrence
Sveti Ivan Zelina, Zagrebačka županija, Croatia