Distance from Lansdowne to Aleksandrow Lodzki
The shortest distance (air line) between Lansdowne and Aleksandrow Lodzki is 4,419.75 mi (7,112.89 km).
How far is Lansdowne from Aleksandrow Lodzki
Lansdowne is located in Virginia, United States within 39° 5' 3.84" N -78° 30' 57.96" W (39.0844, -77.4839) coordinates. The local time in Lansdowne is 14:10 (27.08.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 20:10 (27.08.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,419.75 miles which is equal to 7,112.89 km.
Lansdowne, Virginia, United States
Related Distances from Lansdowne
Aleksandrow Lodzki, Łódzki, Poland