Distance from Langley Park to Sessa Aurunca
The shortest distance (air line) between Langley Park and Sessa Aurunca is 4,566.01 mi (7,348.29 km).
How far is Langley Park from Sessa Aurunca
Langley Park is located in Maryland, United States within 38° 59' 22.92" N -77° 1' 9.12" W (38.9897, -76.9808) coordinates. The local time in Langley Park is 15:28 (25.08.2025)
Sessa Aurunca is located in Caserta, Italy within 41° 13' 59.88" N 13° 55' 59.88" E (41.2333, 13.9333) coordinates. The local time in Sessa Aurunca is 21:28 (25.08.2025)
The calculated flying distance from Sessa Aurunca to Sessa Aurunca is 4,566.01 miles which is equal to 7,348.29 km.
Langley Park, Maryland, United States